(2x-3)(2x+2)=4x^2

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Solution for (2x-3)(2x+2)=4x^2 equation: 



(2x-3)(2x+2)=4x^2

We move all terms to the left:

(2x-3)(2x+2)-(4x^2)=0

determiningTheFunctionDomain
-4x^2+(2x-3)(2x+2)=0

We multiply parentheses ..

-4x^2+(+4x^2+4x-6x-6)=0

We get rid of parentheses

-4x^2+4x^2+4x-6x-6=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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